4[-4(2x+3)+2(5x-4)]=

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Solution for 4[-4(2x+3)+2(5x-4)]= equation:


Simplifying
4[-4(2x + 3) + 2(5x + -4)] = 0

Reorder the terms:
4[-4(3 + 2x) + 2(5x + -4)] = 0
4[(3 * -4 + 2x * -4) + 2(5x + -4)] = 0
4[(-12 + -8x) + 2(5x + -4)] = 0

Reorder the terms:
4[-12 + -8x + 2(-4 + 5x)] = 0
4[-12 + -8x + (-4 * 2 + 5x * 2)] = 0
4[-12 + -8x + (-8 + 10x)] = 0

Reorder the terms:
4[-12 + -8 + -8x + 10x] = 0

Combine like terms: -12 + -8 = -20
4[-20 + -8x + 10x] = 0

Combine like terms: -8x + 10x = 2x
4[-20 + 2x] = 0
[-20 * 4 + 2x * 4] = 0
[-80 + 8x] = 0

Solving
-80 + 8x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '80' to each side of the equation.
-80 + 80 + 8x = 0 + 80

Combine like terms: -80 + 80 = 0
0 + 8x = 0 + 80
8x = 0 + 80

Combine like terms: 0 + 80 = 80
8x = 80

Divide each side by '8'.
x = 10

Simplifying
x = 10

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